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Inductance loading

Many gaz filled rectifiers and some high vaccum types cannot withstand heavy start up currents. Furthermore, as previopus formula show, output voltage tex2html_wrap_inline159 is widely influenced by load characteristics in the case of capacitive loading : when designing a class B amplifier, whose dynamic impedance is dependent on output power level, capacitive loading can yield to unacceptably high mean voltage varaiations. In those cases, inductive loading can be the best answer.

Computation of the inductance L that is wired in serie with the load is done by considering hum current tex2html_wrap_inline245 flowing thru it : if it is higher than mean current tex2html_wrap_inline183, a part of the cycle will exhibit current reversal, which must be avoided. This condition on tex2html_wrap_inline245 will put a minimum value on L. Let us note first tha mean value of voltage before the coil is :
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Where tex2html_wrap_inline255 is the so-called arc voltage, non zero if a gaz filled diode is used. In the following, we will assume tex2html_wrap_inline257 for easy writing of formula : if needed, it can be taken into account easely. Using the expression of shirt-circuit current, previous formula becomes :
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Hum voltage in the case of an inductive loading is the one that would have been obtained with an unloaded rectifier. We can assume, with a fairly good approximation, that this voltage is a complete sine wave with amplitude :
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Formula giving amplitude tex2html_wrap_inline209 of fundamental wave can be used here, taking tex2html_wrap_inline191 as opening angle. In the case of a biphased rectifying, we have for example :
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Amplitude of alternating current thru the self is then :
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If one wants that current never vanishes, this last value must be no higher than tex2html_wrap_inline183, which yield to :
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or equivalently, using tex2html_wrap_inline153 :
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For a 50Hz mains, this can be writtent :
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With the same computation, and for a triphased rectifying, one has :
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and in the hexaphased case :
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It can be noted the interest of using haxaphased current when working with an inductive load!

Computation of RMS current at transformer secundary is difficult than with a capacitive loading. It is possible yet to admit that with high values of self, current is nearly a rectangular wave, yielding :
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next up previous
Next: Filters Up: Power supplies Previous: Capacitive loading

Stephane Puechmorel
Tue Jul 15 10:57:31 WET DST 1997